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A gaseous mixture containing He, CH(4)" ...

A gaseous mixture containing `He, CH_(4)" and "SO_(2)` was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially? If mixture contain `He, CH_(4)" and "SO_(2)` in 1 : 2 : 3 mole ratio

A

`2 : 2 : 3`

B

`6 : 6 : 1`

C

`sqrt(2) : sqrt(2) : 3`

D

`4 : 4 : 3`

Text Solution

Verified by Experts

The correct Answer is:
D
`(n._(He))/(n._(CH_4))= (1)/(2)sqrt((16)/(4))= (1)/(2)`
`(n._(He))/(n._(SO_2))= (1)/(3)sqrt((64)/(4))= (4)/(3)`
`n._(He) : n._(CH_4) : n._(SO_2)= 4 : 4 : 3`.
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