The compressibility factor for nitrogen at 330 K and 800 atm is `1.90` and at 570 K and 200 atm is `1.10`. A certain mass of `N_2` occupies a volume of `1 dm^(3)` at 330 K and 800 atm. Calculate volume occupied by same quantity of `N_(2)` gas at 570 K and 200 atm.

Options

A. `1L`
B. `2L`
C. `3L`
D. `4L`

Answer

D

Explanation

`Z= (PV)/(nRT), 1.90= (1xx 800)/(n xx R xx 330), n = (1 xx 800)/(1.90 xx R xx 330)`
`Z= 1.10= (V xx 200)/(n xx R xx 570)`
`1.10= (V xx 200 xx 1.90 xx R xx 330)/(800 xx R xx 570)V= 4L`.