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A given volume of ozonized oxygen (conta...

A given volume of ozonized oxygen (containing 60% oxygen by volume) required 220 sec to effuse which an equal volume of oxygen took 200 sec only under the conditions. If density of `O_(2)" is "1.6 g"/"L` then find density of `O_(3)`.

A

`1.936 g"/"L`

B

`2.16 g"/"L`

C

`3.28 g"/"L`

D

`2.44 g"/"L`

Text Solution

Verified by Experts

The correct Answer is:
D
Let V mL of gas efused, `(V"/"220)/(V"/"200)= sqrt((d_(O_2))/(d_("mix"))) implies d_("mix")= 1.6xx (1.1)^(2)= 1.936 g"/"L`
Let densityy of ozone is d, In 100 volume ozonized oxygen, 60% and 40% by volume `O_3` is present.
Mass of mixture = mass of zone + mass of oxygen
`100 xx 1.936 = 40xx d +60xx 1.6 implies " density of "O_(3)" is "2.44 g"/"L`.
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