Calculate the degree of hydrolysis of `0.15 M` solution of sodium acetate at 298 K . Dissociation constant of `CH _(3) COONa` is `1. 75 xx 10 ^(-5)` . `K _(w) = 1. 00 8 xx 10 ^(-14)`

Explanation

`K _(b) = ( K _(w))/( K _(b)) = (1. 00 8 xx 10 ^(-14))/( 1. 75 xx 10 ^(-5))= 5. 76 xx 10 ^(-10)`
Assuming degree of hydrolysis to be very small,
Degre of hydrolysis of `CH _(3) COONa , x = sqrt (K _(h // C) )= sqrt (( 5. 76 xx 10 ^(-10))/( 0. 15)) = 3.84 xx 10 ^(-5)`