The dissociation constant of `NH _(4) OH at 298 K is 1. 81 xx 10 ^(-5).` Calculate the degree of hydrolysis of `0.02 M` solution of ammonium chloride, `K _(w) = 1. 008 xx 10 ^(-14).`

Explanation

`K _(h) = (K _(w))/( K _(b)) = (1. 008 xx 10 ^(-14))/( 1. 81 xx 10 ^(-5))= 5.569 xx 10 ^(-10)`
Assuming that the degree of hydrolysis is very small,
Degree of hydrolysis of `NH _(4) Cl, x = sqrt ( K _(h) //C) = sqrt (( 5.569 xx 10 ^(-10))/(0.02)) = 1.1975 xx 10 ^(-6)`