Calculate the degree of hydrolysis of `0.01 M` solution of ammonium acetate at 298 K. Dissociation constants of HCOOH and `NH _(4) OH ` are `1. 75 x 10 ^(-5) and 1. 81 J xx 10 ^(-5)` respectively. `k _(w) = 1. 008 xx 10 ^(-14).`

Explanation

`K _(h) = (K _(w))/( K _(a) xx K _(b) ) = (1.008 xx 10 ^(-14))/(1.75 xx 10 ^(-5) xx 1. 81 xx 10 ^(-5)) = 3. 182 xx 10 ^(-5) and K _(h) = x ^(2)// (1 - x) ^(2)`
As x is vert small, it may be neglected, therefore,
Degree of hydrolysis of `(NH _(4)) _(2) C _(2) O _(4), x = sqrt ( K _(h)) = sqrt ( 3.182 xx 10 ^(-5)) = 5.64 xx 10 ^(-3)`