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For the reaction, H (2 (g) )+ CO (2) (g...

For the reaction, `H _(2 (g) )+ CO _(2) (g) hArr CO (g) + H _(2) O (g),` if the initial concentration of `[H _(2) ] =[CO _(2)]` and x mol`L ^(-1) ` of `H,_(2)` is consumed at equilibrium, the correct expression of `K_(P)` is:

A

`(x ^(2))/( (1- x ) ^(2))`

B

`((1 + x ) ^(2))/( (1 -x ) ^(2))`

C

`(1 + x ^(3))/( (2 + x ) ^(2))`

D

`(x ^(2))/( 1 + x ^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`H _(2) (g) + CO _(2) (g) hArr CO (g) + H _(2) O (g)`
`{:(t=0, x,x ,0,0),(t=t _(Bq), 1-x, 10x, x, x):}`
`therefore K = ([ CO ][H _(2) O ])/( [H _(2) ][CO _(2)] ) = (x ^(2))/( (1- x) ^(2))`
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