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In a 10 L vessel, HI was heated to attai...

In a 10 L vessel, HI was heated to attain equilibrium. At equilibrium 327.68 g HI, 406.4 g `I_(2)` 15.6g `H_(2)` were present in the mixture. Calculate `K_(c)` if the mixture is transferred to 5L vessel.

A

`0.029 `

B

`0.059 `

C

`0.019`

D

`0.91`

Text Solution

Verified by Experts

The correct Answer is:
C
`2HI hArr H _(2) + I _(2), " " Now K _(a) = ([ H _(2) ] [I _(2) ])/( [HI]^(3))`
Given that `[H _(2) ] = (w _(H _(2)))/( m _(H _(2)) xx V _(L))= (15.6 )/(2 xx 10 ) = 0 .78 [I _(2)]= (w _(1 _(2)))/( m _(I _(2)xx V _(1 )))= ( 406.4)/(254 xx 10) = 0.16`
`[HI] = ( w _(Hl))/( m _(Hl) xx V _(L)) = ( 3276 . 8)/(128 xx 1 0 ) = 2. 56 or K _(c) = (0 .78 xx 0. 16)/((2. 56) ^(2)) = 0.019`
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