The equilibrium constant for, `H _(2 (g)) + CO _(2 (g)) hArr H _(2) O _((g)) + CO _((g)) is 1.80 at 1000 ^(@)C.` If 1.0 mole of `H_(2) ` and 1.0 mole of `CO_(2)` are placed in one litre flask, the final equilibrium concentration of CO at `1000^(@)C` will be: `0.573 M`, `0.385 M`, `5.73 M`, `0.295M`

Options

A. `0.573 M`
B. `0.385 M`
C. `5.73 M`
D. `0.295M`

Answer

A

Explanation

`CO _(2) + H _(2) hArr H _(2) O + CO `
`{:(1,1,0, 0),((1-x), (1-x), x, x):}`
`therefore K _(c) = (x ^(2))/( (1 -x ) ^(2)) or (x)/ (1-x) = sqrt (K _(c)) = sqrt (1.8),`
`therefore (x)/(1- x) = 1. 34 , therefore x = 0.573`