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The equilibrium constant for the reactio...

The equilibrium constant for the reaction, `N _(2 (g)) + O _(2(g)) hArr 2 NO _((g))` at temperature Tis `4 xx 10 ^(-4).` The value of `K_(c)` for the reaction. `NO _((g)) hArr (1)/(2) N _(2 (g)) + (1)/(2) O _(2 (g))` at the same temperature is :

A

`0.02`

B

`50`

C

`4 xx 10 ^(-4)`

D

`2.5 xx 10 ^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`N _(2) + O _(2) hArr 2 NO `
`K _(c _(1)) = ([ NO ] ^(2))/( [ N_(2) ][O _(2)])= 4 xx 10 ^(-4) " " NO hArr (1)/(2) N _(2) + (1)/(2) O _(2)`
`K _(c _(2)) = ([ N (2) ] ^( 1//2) [ O _(2) ] ^(1//2))/([NO]) " " K _(c _(2)) = sqrt ((1)/( K _(c _(1)))) = sqrt ((1)/( 4 xx 10 ^(-4))) = 50`
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