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For a fairly concentrated solution of a ...

For a fairly concentrated solution of a weak electrolyte `A _(y) , B _(y)` the degree of dissociation is given by

A

`alpha = sqrt (( K _(aq) XY)/( C ))`

B

`alpha = sqrt ((K _(eq) C )/((x + y)))`

C

`alpha = sqrt (( K _(aq) XY)/( C ))`

D

`alpha = ((K _(eq))/(C ^(x + y - 1 ) X ^(x ) y ^(y)))^( 1 (x + y))`

Text Solution

Verified by Experts

The correct Answer is:
A
The ratio can be expressed as
`A_(x) B _(y) hArr x A ^( y +) + y B ^( x-)`
`{:("Initial concentration", C , 0, 0),("Conc. at equilibrium", C (1-alpha ) , xCalpha, yC alpha):}`
`K _(eq) = ((x C alpha ) ^(x) (y C alpha ) ^(x) (y C alpha ) ^(y))/(C ( 1- alpha)) = ((x C alpha ) ^(x) (y C alpha ) ^(y))/( C) ` (Taking `1- alpha =1 ) =(x ^(x) y ^(y) C ^(x + y) alpha ^( x + y))/( C) = x ^(x) y ^(y) C ^(x + y + 1) alpha ^( x + y)`
`alpha = ((K _(eq))/( x ^(x) y ^(y) C^(x + y + 1))) ^( 1 (x + y))`
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