For the reaction, `H _(2 (g)) + I _(2 (g)) hArr 2 HI _((g)) K = 47.6,` if the initial number of moles of each reactant and product is 1 mole, then at equilibrium:

Options

A. `[I_(2)]= [H_(2)], [I_(2)]lt[HI]`
B. `[I_(2)]lt [H_(2)], [I_(2)]=[HI]`
C. `[I_(2)]= [H_(2)], [I_(2)]=[HI]`
D. `[I_(2)]gt [H_(2)], [I_(2)]=[HI]`

Answer

C

Explanation

`K _(c) = ([ HI ]^(2))/( [ H_(2) ][ I _(2) ])`
`[H _(2) ] =[I_(2)]` will be same at equilibriu, since it is same at initial state.