`XY_(2)` dissociates as: `XY _(2 (g)) hArr XY _((g))+Y_((g).` Initial pressure of `XY_(2)` is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of `K_(P)` is:

Options

A. 50
B. 100
C. 200
D. 400

Answer

B

Explanation

`XY _(2(g)) hArr XY _((g)) + Y _((g))`
`600 -x " x" " "x`
`600 + x = 800 or x = 200`
Applying law of mass action `K _(P) =( 200 xx 200)/(400) = 100`