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NH (4)COONH (2 (s)) hArr 2 NH (3 (g)) + ...

`NH _(4)COONH _(2 (s)) hArr 2 NH _(3 (g)) + CO _(2 (g))` If equilibrium pressure is 3 atm for the above reaction: `K_(P)` will be:

A

4

B

27

C

`4//27`

D

`1//27`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(NH _(3)) P _(CO _(2)) = 2:1 therefore P _(NH _(3)) = 2 atm, P _(CO _(2)) = 1 atm implies K _(P) =[P _(NH _(3)) ] ^(2) [ P_(CO _(2))]= 2 xx 1 =4`
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