Home
Class 11
CHEMISTRY
The pH of a solution obtained by mixing ...

The pH of a solution obtained by mixing 50 mL of 0.4 NHCI and 50 mL of 0.2 N NaOH is:

A

`-log 2`

B

`-log 0.2`

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
`N _(1) V _("1 acid") - N _(2) V _(2 "based") = N _(R) (V _(1) + V _(2))`
`0.4 xx 50 - 0.2 xx 50 = N _(R) xx 100 , N _(R) = 0.1 therefore [H^(+) ] = 0.1 M`
`pH =- log [H^(+)] =- log 0.1 = 1`
Promotional Banner

Similar Questions

Explore conceptually related problems

The pH of a solution obtained by mixing 50 mL of 1 N HCl and 30 mL of 1 N NaOH is [log 2.5 =0.3979]

The pH of the resultant solution obtained by mixing 20mL of 0.01 M HCl and 20mL of 0.005M Ca(OH)_(2) is

What is the pH of a solution formed by mixing 40 ml of 0.1 M HCI and 10 ml 0.45 M NaOH?

The molarity of a solution obtained by mixing 750mL of 0.5 M HCl with 250 mL of 2M HCl will be

Calculate the pH of a solution when (i) 49.9 ml of 0.1 M NaOH and (ii) 50.0 ml of 0.1M NaOH added to 50 ml of 0.1 M HCl

The pH of the solution obtained by mixing equal volumes of two solutions of pH = 3 and pH = 5 is (log 3 = 0, log 5 = 0.7)