Which is correct statement if `N_(2)` is added at equilibrium condition? `N _(2) + 3H _(2) hArr 2 NH _(3)`

Options

A. The equilibrium will shift to forward direction because according to Ilnd law of thermodynamics the entropy must increases in the direction of spontaneous reaction.
B. The condition for equilibrium is `G _(N_(2)) + 3 G _(H _(2)) = 2 G _(NH _(3))` where Gibbs free energy per mole of the gaseous species measured at that partial pressure. The condition of equilibrium is unaffected by the use of catalyst, which increases the rate of both the forward and reverse reactions to the same extent.
C. The catalyst will increase the rate of forward reaction bya and that of reverse reaction by `beta.`
D. Catalyst will not alter the rate of either of the reaction.

Answer

B

Explanation

Because change in Gibos free energy is given by : `Delta G` (reaction ) =` Delta G` (products) `-Delta G` (reactants) Also, catalyst ony speeds up the reaction without affecting the equilibrium conditions.