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The degree of dissociation is 0.4 at 400...

The degree of dissociation is 0.4 at 400 K and 1.0 atm for the gaseous reaction. `PCL _(5) hArr PCl _(3) + Cl _(2)` Assuming ideal behaviour of all the gases, calculate the density of equilibrium mixture at 400 K and 1.0 atmosphere. (Atomic mass of P=31.0 and Cl= 35.5)

A

7.39 g/L

B

3.54 g/L

C

6.92 g/L

D

4.53 g/L

Text Solution

Verified by Experts

The correct Answer is:
D
`PCl _(5) hArr PCl _(3) + Cl _(2)`
`{:(1, 0, 0, "initial mole"), (1-04, 0.4, 0.4, "mole at equilibrium"):}`
Total mole at equilibrium `= 1 - 0.4 + 0.4 + 0.4 = 1. 4`
`("Normal "m _(PCl _(5)))/( "Observed" M _(PCL _(5))) = 1 + alpha = 1. 4 ` Observed ` m _(PCl _(5)) = ( 208 . 5)/(1 .4)`
For `PV = (m)/(w) RT` at equilibrium , `(w)/(v) = (Pm )/(RT) = (1 xx 208.5 )/( 1. 4 xx 0. 0 82 xx 400) = 4 53` g/litre
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