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For the equilibrium system 2HX (g) hArr ...

For the equilibrium system `2HX (g) hArr H _(2) (g) +X _(2) (g)` the equilibrium constant is `1.0 xx10^(-5).` What is the concentration of HX if the equilibrium concentration of `H_(2) and X_(2)` are `1.2 xx10^(-3) M, and 1.2 x10^(-4) M `respectively?

A

`12 xx 10 ^(-4) M`

B

`12 xx 10 ^(-3) M`

C

`12 xx 10 ^(-2) M`

D

`12 xx 10 ^(-1) M`

Text Solution

Verified by Experts

The correct Answer is:
C
`2 HX (g) hArr H _(2) (g) + X_(2) (g)`
At equilibrium `1.2 xx 10 ^(-3) M 1.2 xx 10 ^(-4) M`
`K = ([ H _(2) ] [X _(2) ] )/( [HX ] ^(2)) , 10 ^(-5) (1.2 xx 10 ^(-3) xx 1. 2 xx 10 ^(-4))/([HX] ^(2)) implies [HX]= sqrt ((.2 xx 1.2 xx 10 ^(-7))/( 10 ^(-5))) = 1.2 xx 10 ^(-1) = 12 x 10 ^(-2) M`
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