Home
Class 11
CHEMISTRY
The %yield of ammonia as a function of t...

The %yield of ammonia as a function of time in the reaction `N _(2) (g) + 3 H _(2) (g) hArr 2 NH _(3) (g). Delta H lt 0 at (p , T _(1))` is given below. If this reaction is conducted at `(P_(1) T_(2)),` with `T_(2) gt T_(1)` the % yield of ammonia as a function of time is represented by

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
C

`N _(2) (g) + 3 H _(2) (g) hArr 2 NH _(3) Delta H lt 0` (exothermic) . For exothermic reaction, high temperature favours the reaction in backwrd direction ie. Yield of reaction decreases.
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the effect of temperature on the reaction? N 2 ( g ) + 3 H 2 ( g ) ↔ 2 N H 3 ( g ) + H e a t

The graph for the reaction N_2(g)+3H_2(g)harr2NH_3(g)+heat is given below. Indentify and write the reactions C and D

The equiiibrium constant for the reaction N_(2)(g)+3H_(2) hArr 2NH_(3)(g) and 2N_(2)(g) +6H_(2) harr 4NH_(3)(g) "are" K_(1) and K_(2) respectively. The relationship between K_(1) and K_(2) is

Assertion : For the reaction 2 NH _(3 (g)) to N _(2 (g)) + 3 H _(2 (g)), Delta H gt Delta U Reason : Enthalpy change is always greater than internal energy change

If the K_(c) of the reaction N_(2)(g)+3H_(2)(g) iff 2NH_(3)(g) at 750 K is 49, then the K_(c) of the reaction NH_(3)(g) iff 1/2N_(2)(g)+3/2H_(2)(g) at the same temperature is

Justify the following reaction is redox reaction 4NH_3(g) + 5O_2 (g) to 4NO (g) + 6H_2O (g)

In Haber's process, ammonia is manufactured according to the following reaction N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) , Delta H^(@) = -2.4 kJ The pressure inside the chamber is maintained at 200 atm and temperature at 500^(@)C . Generally this reaction is carried out in presence of Fe catalyst. The preparation of ammonia by Haber's process is an exothermic reaction. If the preparation follows the following temperature pressure relationship for its % yield. Then for temperature T_(1), T_(2) and T_(3) , the correct option is :