For the reaction `N _(2) O _(4) (g) hArr 2NO _(2) (g), `the value of `K _(p)` is `1.7 xx10^(3) at 500 K and 1.7xx10^(4) at 600 K.` Which of the following is/are correct?

Options

A. The proportions of `NO_(2)` in the equilibrium mixture is increased by decrease in pressure.
B. The standard enthalpy change for the forward reaction is negative.
C. Units of `K_(2)` are `atm^(-2)`
D. At 500 K the degree of dissociation of `N_(2) O_(4)` decreases by 50% by increasing the pressure by 100%

Answer

A

Explanation

`Delta n = 1- 1 =1 `
That is, with the decrease of pressure, reaction shifts towards right, i.e. proportions of `NO _(2)` increases.