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Equilibrium constant K(P) for 2H (2) S (...

Equilibrium constant `K_(P)` for `2H _(2) S _((g)) hArr 2 H _(2 (g)) + S _(2 (g)) is 0. 0 11 8 atm at 1065 ^(@)C` and heat of dissociation is 42.4 kcal. Find equilibrium constant at `1132^(@)C.`

A

`0.025 atm`

B

`0.052 atm`

C

`0.52 atm`

D

`0.075 atm`

Text Solution

Verified by Experts

The correct Answer is:
A
According to van.t Hoff equation
`therefore 2.303 log _(10) ""(K _(p2))/(K _(P 1)) = (Delta H )/(R) [(T_(2)- T _(1))/( T _(2) xx T _(1))] = ( 42.4 xx 10 ^(3))/( 2 ) [ ( 1405- 1338)/(1405 xx 1338)]`
`therefore ( K _(p 2 ))/( K _(p 1 )) = 2. 12 9 implies K _(p 2) = 2. 129 xx 0. 0 118 = 0.025 atm`
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