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The oxidation state of most electronegat...

The oxidation state of most electronegative element in the products of the reaction, 'BaO_2' with dil. 'H_2 SO_4' are

A

`0 and -1`

B

`-1 and -2`

C

`-2 and 0`

D

`-2 and + 1`

Text Solution

Verified by Experts

The correct Answer is:
B
Oxygen in `h_2o_2` and `BaSO_4` (formed) has –1 and 2 oxidation number respectively.
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