Number of moles of `K_2Cr_2O_7`, reduced by one mole of `Sn^(2+)` ions is:

Options

A. `1//3`
B. `1//6`
C. `2//3`
D. `1`

Answer

A

Explanation

`Cr_2O_7^(2-) + 3Sn^(2+) + 14H^(+) to 3Sn^(4+) + 2Cr^(3+) + 7H_2O`
3 mol of `Sn^(2+)` react with 1 mol of `Cr_2O_7^(2-)`. So, 1 mol of `Sn^(2+)` will react with (1/3) mol of `Cr_2O_7^(2-)`