When `KMnO_4` acts as an oxidising agent and ultimately form `MnO_4^(2-), MnO_2, Mn_2O_3`, and `Mn^(2+)`, then the numbers of electrons transferred in each case, respectively, are

Options

A. 4, 3, 1, 5
B. 1,5, 3, 7
C. 1,3,4,5
D. 3, 5, 7, 1

Answer

C

Explanation

`e^(-) + MnO_4^(Theta) to MnO_4^(2-) " " 3e^(-) + MnO_4^(Theta) to MnO_2`
`4e^(-) + 2MnO_4^(Theta) to Mn_2O_3 " " 5e^(-) + MnO_4^(Theta) to Mn^(2+)`