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The volume of 10 volume H2O2 required ...

The volume of 10 volume `H_2O_2` required to liberate 500 mL of `O_2` at STP is

A

25mL

B

50mL

C

100mL

D

125mL

Text Solution

Verified by Experts

The correct Answer is:
B
10 volume `H_2O_2` means 10 mL of `O_2` is produced at STP from 1 mL of 10 vol `H_2O_2`.
Hence 500 mL of `O_2` is produced at STP from `500/10 = 50 mL `of 10 vol `H_2O_2`
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