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Which of the following orders of boiling...

Which of the following orders of boiling points of hydrides of Group 16 is correct?

A

`H_2O gt H_2Se gt H_2S`

B

`H_2O gt H_2S lt H_2Se`

C

`H_2O lt H_2S gt H_2Se`

D

`H_2O lt H_2S lt H_2Se`

Text Solution

Verified by Experts

The correct Answer is:
B
Because of hydrogen bonding, the boiling point of `H_2O` is greater than that of `H_2S`. The boiling point of `H_2S` is smaller than `H_2` Se as the former is a lighter molecule.
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