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The increasing order of reducing propert...

The increasing order of reducing property of `NaH, MgH_2` and `H_2O` is

A

`NaH lt H_2O lt MgH_2`

B

`MgH_2 lt H_2O lt NaH`

C

`H_2O lt MgH_2 lt NaH`

D

`NaH lt MgH_2 lt H_2O`

Text Solution

Verified by Experts

The correct Answer is:
C
Metal hydrides are stronger reducing agents than non-metal hydrides. Thus, `H_2O` is a weaker-reducing agent and NaH due to more electropositive nature of Na is strongest reducing agent among the given. Thus, the correct order is `H_2O lt MgH_2 lt NaH`.
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