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10mL of H2O2 solution (volume strength=x...

10mL of `H_2O_2` solution (volume strength=x) requires-10 mL of `N//0.56 MnO_4^(-)` solution in acidic medium. Hence x is

A

`0.56`

B

`5.6 `

C

`0.1 `

D

`10`

Text Solution

Verified by Experts

The correct Answer is:
D
N of `H_2O_2` =Volume strength/5.6= `x//5.6`
mEq. of `H_2O_2 -= "mEq. of " MnoO_(4)^(-) therefore N_1V_1 -= N_2V_2`
`x/(5.6) xx 10 mL = 1/(0.56) xx 10 mL therefore x = .10.` volume strength
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