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A compound (60 gm) on analysis gave C = ...

A compound (60 gm) on analysis gave C = 24 gm, H = 4 gm, and O = 32 gm. Its empirical formula is:

A

`C_(2)H_(2)O`

B

`C_(2)H_(4)O_(2)`

C

`CH_(2)O`

D

`CH_(2)O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:("C",:,"H",:,"O"),((24)/(12),:,(4)/(1),:,(32)/(16)),(2,:,4,:,2):}`
Empirical Formula = `CH_(2)O`
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