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An organic compound contains C=40%, O=53...

An organic compound contains `C=40%, O=53.5% and H=6.5%`. The empirical formula of the compound is:

A

`CH_(2)O`

B

`C_(2)H_(4)O`

C

`C_(6)H_(12)O_(6)`

D

`C_(2)H_(4)O_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:("C",:,"H",:,"O"),((40)/(12),:,(6.5)/(1),:,(53.5)/(16)),(3.33,:,6.5,:,3.34),(1,:,2,:,1):}`
Empirical Formula = `CH_(2)O`
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