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A compound contains 38.8%C, 16%H, and 45...

A compound contains 38.8%C, 16%H, and 45.2%N. The formula of the compound would be:

A

`CH_(3)NH_(2)`

B

`C_(2)H_(5)CN`

C

`CH_(3)CN`

D

`CH_(2)(NH_(2))_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:("C",:,"H",:,"N"),((38.8)/(12),:,(16)/(1),:,(45.2)/(14)),(3.23,:,16,:,3.2),(1,:,5,:,1):}`
`MF=CH_(5)N=CH_(3)NH_(2)`
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