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0.14 gm of an acid required 12.5 ml of 0...

0.14 gm of an acid required 12.5 ml of 0.1 N NaOH for complete neutralisation. The equivalent mass of the acid is:

A

63

B

56

C

45

D

112

Text Solution

Verified by Experts

The correct Answer is:
D
mEq. Of NaOH = `12.5xx0.1=1.25`
mEq. Of acid = mEq. Of NaOH
Equivalent = `("Wt.")/("Ew")therefore Ew=("Wt.")/("Equivalent")=(0.14)/(1.25xx10^(-3))=112`
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