500 mL of a hydrocarbon gas burtn in excess of oxygen yielded 2500 mL of `CO_(2)` and 3.0 litre of water vapour (all volumes measured at the same temperature and pressure). The formula of the hydrocarbon is:

Options

A. `C_(3)H_(6)`
B. `C_(2)H_(4)`
C. `C_(5)H_(12)`
D. `CH_(4)`

Answer

C

Explanation

`C_(x)H_(y)+[x+(y)/(4)]O_(2)rarrxCO_(2)+(y)/(2)H_(2)O(v)`
`{:(500,0,0),(0,500x,(y)/(2)xx500):}`
Now, 500x = 2500 `therefore x=5, 500(y)/(2)=3000 therefore y=12 therefore` Alkane is `C_(5)H_(12)`.