0.0833 mole of a carbohydrate of empiric...

0.0833 mole of a carbohydrate of empirical formula `CH_(2)O` contains 1.00 g of hydrogen. The molecular formula of the carbohydrate is:

`C_(5)H_(10)O_(5)`

`C_(3)H_(4)O_(3)`

`C_(12)H_(22)O_(11)`

`C_(6)H_(12)O_(6)`

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The correct Answer is:

1 mole of carbohydrate will contain `(1)/(0.0833)g`of hydrogen, ie, 12 g hydrogen.
`therefore` The molecular formula of the compound will be `C_(6)H_(12)O_(6)`.

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