Analysis of an organic compound gave 74%...

Analysis of an organic compound gave 74% C, 8.65% H and 17.3% N. What is the empirical formula of the compound.

`C_(5)H_(8)N`

`C_(10)H_(12)N`

`C_(5)H_(7)N`

`C_(10)H_(14)N`

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The correct Answer is:

`therefore` Empirical formula of the compound = `C_(5)H_(7)N`

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