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In a compound C, H and N atoms are prese...

In a compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. Mol wt. of compound is 108, its mol. formula is

A

`C_(2)H_(6)N_(2)`

B

`C_(3)H_(4)N`

C

`C_(6)H_(8)N_(2)`

D

`C_(9)H_(12)N_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`13.5g-=9gC-=1gH=3.5gN`
`therefore 108g-=(9xx108)/(13.5)gC-=(1xx108)/(13.5)gH-=(3.5xx108)/(13.5)gN` `-=(9xx108)/(13.5xx12)"mol C"=(1xx108)/(13.5xx1)"mol H"=(3.5xx108)/(13.5xx14)"mol N"therefore` Molecular formula = `C_(6)H_(8)N_(2)`
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