Home
Class 12
CHEMISTRY
A galvanic cell is constructed as follow...

A galvanic cell is constructed as follows. A half ceil consists of a platinum wire immersed in a solution containing 1.0M of `Sn^(2+)` and 1.0 M of `Sn^(4+)` and another half cell has a thallium rod immersed in a 1.0 M solution to `TI^(+)`
Given : `Sn^(4+)+2e^(-)toSn^(2+),E^(@)=+0.13V`
and `TI^(+)+e^(-)toT,,E^(@)=-0.34V`
What is the cell voltage if the `TI^(+)` concentration is increased tenfold?

A

0.592V

B

0.411V

C

0.459V

D

0.47V

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • REDOX REACTION & ELECTROCHEMISTRY

    BRILLIANT PUBLICATION|Exercise QUESTION (ELECTROCHEMISTRY) (LEVEL -II) (ASSERTION-REASON)|3 Videos
  • REDOX REACTION & ELECTROCHEMISTRY

    BRILLIANT PUBLICATION|Exercise QUESTION (ELECTROCHEMISTRY) (LEVEL -I) (HOMEWORK)|20 Videos
  • POLYMERS, BIOMOLECULES AND CHEMISTRY IN EVERYDAY LIFE

    BRILLIANT PUBLICATION|Exercise LEVEL -III (Comprehension Type) |12 Videos
  • SOLID STATE

    BRILLIANT PUBLICATION|Exercise LEVEL-3 (Linked Comprehension Type)|10 Videos

Similar Questions

Explore conceptually related problems

A galvanic cell is constructed of two hydrogen electrodes, one immersed in a solution with H^+ at 1M and the other in 1M KOH. Calculate E_(cell) . If 1M KOH solution is replaced by 1M NH_3 , will E_(cell) be higher or lower than in 1M KOH?

IF the following half cells have the E^@ values as Fe^(3+)+e to Fe^(2+), E^@=0.77Vand Fe^(2+)+2e to Fe, E^@=-0.44V the E^@ of the cell half cell Fe^(3+)+3e to Fe will be

The emf of a cell consisting of a copper and a lead electrode immersed in 1M solution of salts of these metals is 0.47V. Will the emf change if 0.001 solutions are taken?

Calculate the electrode potential of copper electrode in a 0.1 M copper sulphate solution at 25^(@) C. (E^(@)(Cu^(2+)|Cu) = 0.34V) .

The standard potentials, E^@ for the half reaction are as Zn=Zn^(2+)+2e^(-) , E^@=0.76V Fe=Fe^(2+)+2e^(-) , E^@=0.41V The emf for the cell reaction Fe^(3+) +Zn to Zn^(2+)+Fe is

From the following E^@ values of half cells (i) A to A^(+)+e, E^@=+1.2V (ii) B^(-) to B+e, E^@=-2.1V (iii) C to C^(2+) +2e, E^@=0.38V (iv) D^(-2) to D^(-) +e, E^@=-0.59V What combination of two half cells would result in a cell with the largest potential?

Calculate the potential of a Daniel cell, initially containing 1 litre each of 1M Cu^(2+) and 1M Zn^(2+) after a passage of 1 times 10^5 coulombs of charge . E_(Cu^(2+),Cu)^@=+0.34V, E_(Zn^(2+),Zn)^@=-0.76V

The half-cell reaction for the corrosion. 2H^(+)+1/2O_(2)rarr H_(2)Ol,E^(@)=1.23 V Fe ^(2+)+2e ^(−) →Fe (s);E^(@) =−0.44V Find the triangle G^(@) (in kJ) for the overall reaction:

Construct galvanic cells from the following pairs of half cells and calculate their emf at 25^@C Sn,SnCl_2(1M) E_(Sn^(2+),Sn)^@=-0.14 volt and Fe|FeSO_4 (1M) E_(Fe^(2+),Fe)^@=0.44 volt

BRILLIANT PUBLICATION-REDOX REACTION & ELECTROCHEMISTRY-QUESTION (ELECTROCHEMISTRY) (LEVEL -II)
  1. The voltage of a cell consisting of Ca(s) and Cl(2)(g) is 4.23V under ...

    Text Solution

    |

  2. Consider the cell reaction k2Fe(s)=O(2)(g)+4H(aq)^(+)to2Fe^(2+)+2H(2)O...

    Text Solution

    |

  3. A galvanic cell is constructed as follows. A half ceil consists of a p...

    Text Solution

    |

  4. Given the standard electrod potentials E(Cu^(2+)//Cu)^(@)=0.34v and E(...

    Text Solution

    |

  5. When a Galvanic cell produce current by a spontaneous reaction

    Text Solution

    |

  6. A cell contains two copper electrodes. The negative electrode is in co...

    Text Solution

    |

  7. The emf of the cell Pt, underset(1atm)(H(2(g)))|underset(.01M)(HA)||un...

    Text Solution

    |

  8. For the cell Zn|Zn^(2+)(0.01M)||M((0.001M))^(2+)|M,E("cell")=0.29V. Wh...

    Text Solution

    |

  9. Pt,H(2) (1bar)|HCl(aq)|AgCl(s)|Ag has cell potential 0.92V at 25^(@)C ...

    Text Solution

    |

  10. The equilibrium constant of the reaction 2Fe^(3+)+2I^(-)to2Fe^(2+)+I(2...

    Text Solution

    |

  11. Which of the following is/are true a.Specific conductance denotes co...

    Text Solution

    |

  12. Molar conductivity of a 0.01 M solution of a weak monobasic acids HA i...

    Text Solution

    |

  13. 0.025 M aq. Solution of methanoic acid has molar conductivity 46 S. cm...

    Text Solution

    |

  14. From the following molar conductivities at infinite dilution lamda(m...

    Text Solution

    |

  15. Ionisation constant of acetic acid is 2xx10^(-6). Molar conductivity o...

    Text Solution

    |

  16. 0.04M solution of a weak dibasic acid is 4.23xx10^(-4)S.cm^(-1) The de...

    Text Solution

    |

  17. At 298 K, the conductivity of a saturated solutioni of Agcl in water i...

    Text Solution

    |

  18. One faraday current is passed through molten Na(2)O,MgO and Al(2)O(3)....

    Text Solution

    |

  19. Consider the electrochemical cell between Ag(s) and Cl(2)(g) electrode...

    Text Solution

    |

  20. How many cc of oxygen is released by a current of 2A flowing for 3 min...

    Text Solution

    |