Home
Class 12
CHEMISTRY
The total no.of isomers possible for the...

The total no.of isomers possible for the square planar complex `[MBr_(2)Cl_(2)](SO)_(4)` is
(`SO_(4)^(2-)` here acts as a bidentate ligand)

A

5

B

4

C

3

D

2

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATION COMPOUNDS AND ORGANOMETALLICS

    BRILLIANT PUBLICATION|Exercise Level-II|46 Videos
  • CO-ORDINATION COMPOUNDS AND ORGANOMETALLICS

    BRILLIANT PUBLICATION|Exercise Level-II (Assertion- Reason)|4 Videos
  • CHEMICAL KINETICS

    BRILLIANT PUBLICATION|Exercise LEVEL II|75 Videos
  • COORDINATION COMPOUNDS

    BRILLIANT PUBLICATION|Exercise LEVEL III (Linked Comprehension Type) (Paragraph IV)|3 Videos

Similar Questions

Explore conceptually related problems

The total no. of isomers possible for the complex cation [CrCl_(2)(en)_(2)]^(+) is

The no.of geometrical isomers that can exist for the square planar complex [Pt(NH_(3))Cl(NH_(2)OH)(py)]^(+) is

The number of geometrical isomers possible for the complex [CoL_2Cl_2]^(-) (L = H_2NCH_2 CH_2O^(-)) is

The number of possible isomers of an octạhedral complex [Co(C_2 O_4)_2,(NH_3)_2]^- : 1, 2, 3, 4

Assertion : Only cis-[ Pt(NH_(3))_(2)Cl_(2)] reacts with oxalic acid (H_(2)C_(2)O_(4)) to form [PtCl_(2)("ox")]^(2-) , not the trans isomer. Reason : The oxalate ion is a bidentate ligand which can occupy adjacent positions only.

The number of geometric isomers that can exist for square planar [Pt(Cl)(py)(NH_3)(NH_2OH)]^(+) is (py = pyridine)

Predict the number of unpaired electrons in the squar planar [Pt(CN)_4]^(2-) ion.