Melting point of RbBr is 682^(@)C, while...

Melting point of RbBr is `682^(@)C`, while that of NaF is `988^(@)C`. The principal reason that melting point of NaF is much higher than that of RbBr is that:

the two crystals are not isomorphous

the molar mass of NaF is smaller than that of RbBr

the internuclear distance `r_(c)+r_(a)` is greater for RbBr than for NaF

the bond in RbBr has more covalent character than the bond in NaF

Text Solution

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The correct Answer is:

Lattice energy is high for NaF.

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BRILLIANT PUBLICATION-SOLID STATE-LEVEL-II

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