A certain sample of cuprous sulphide is found to have composition `Cu_(1.8)S`, because of incorporation of `Cu^(2+)` ions in the lattice. What is the mole % of `Cu^(2+)` in total copper content in this crystal?

Options

A. `99.8%`
B. `11.11%`
C. `88.88%`
D. `33.33%`

Answer

B

Explanation

Two `Cu^(+)` replaced by one `Cu^(2+)`, Total loss of Cu = 0.2 mole
So, mole of `Cu^(2+)` present in `Cu_(1.8)S=0.2`
`therefore%" of "Cu^(2+)` in total copper content = `0.2/1.8xx100=11.11`