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When Cl2 gas reacts with hot and concent...

When `Cl_2` gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

A

zero to +1 and zero to +5

B

zero to -1 and zero to +5

C

zero to -1 and zero to +3

D

zero to +1 and zero to -3

Text Solution

Verified by Experts

The correct Answer is:
B
`3Coverset0l_2 + 6NaOH "(conc.)" oversetDeltato 5Naoverset(-1)(Cl) + Naoverset(+5)(Cl)O_3 + 3H_2O`
Here, O.N of Cl changes from 0 in `Cl_2` to -1 in NaCl and form 0 in `Cl_2` to +5 in `NaClO_3`.
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