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Iodine is liberated when potassium iodid...

Iodine is liberated when potassium iodide reacts with a solution of Z n S O 4 C u S O 4 ( N H 4 ) 2 S O 4 N a 2 S O 4

A

`ZnSO_4`

B

`CuSO_4`

C

`(NH_4)_2SO_4`

D

`Na_2SO_4`

Text Solution

Verified by Experts

The correct Answer is:
B
`CuSO_4 + 2KI to CuI_2 + K_2SO_4 , 2CuI_2 to underset"Cuprous iodide"(2CuI) + I_2`
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