Home
Class 12
CHEMISTRY
The intermediate during the addition of ...

The intermediate during the addition of HCl to propene in presence of peroxide is : ` CH_3 CH CH_2 Cl`, `CH_3 C H^(+) CH_3`, `CH_3 CH_2 CH^(.) CH_2`, `CH_3 CH_2 C H_2`,

A

`CH_(3)CHCH_(2)Cl`

B

`CH_(3)CHCH_(3)`

C

`CH_(3)CH_(2)CH_(3)`

D

`CH_(3)CH_(2)CH_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Anti-Markovnikov.s addition is observed only with HBr. Therefore, with HCI, even in the presence of peroxides, reaction occurs through a more stable carbocation intermediate.
Promotional Banner

Similar Questions

Explore conceptually related problems

Which are the branches? CH_3 CH_2 CH(CH_2 CH_2 CH_3) CH_2 CH(CH_3) CH_2 CH_3

Let us represent the main chain. CH_3 CH_2 C(CH_2 CH_2 CH_3) CH_2 CH_2 CH_3

What are the positions of the branches in the compound given below? CH_3 CH_2 CH(CH_3) CH_2 CH(CH_3) CH_2 CH_2 CH_3

Arrange the following compounds in increasing order of their boiling points. CH_3 CHO, CH_3 CH_2 OH, CH_3 OCH_3, CH_3 CH_2 CH_3

The IUPAC name of the following structure [CH_3 CH (CH_3)]_2 C(CH_2 CH_3) C(CH_3) C(CH_2 CH_3)_2 is

The compound which reacts with HBr obeying Markovinkoff's rule is CH_2=CH_2' CH_3 CH=CHCH_3' CH_3 CH_2 CH=CHCH_3' (CH_3), C=CH_2'

The intermediate formed when CH_(3)COOH react with CH_(3)CH_(2)OH in presence of HCl

Arrange the following in the decreasing order of reactivity of addition of Hx. CH_2 = CH_2 , (CH_3)_2C = CH_2 and CH_3-CH = CH = CH_3

The product obtained in a oxymercuration (HgSO_4+H_2 SO_4) of 1 -butyne would be : CH_3 CH_2 COCH_3 , CH_3 CH_2 CH_2 CHO , CH_3 CH_2 CHO+HCHO , CH_3 CH_2 COOH+HCOOH

The correct increasing order of reactivity of halides for SN' reaction is : CH_3 CH_2 Xlt(CH_3)_underline2 CH XltCH_2=CH CH_2 XltPhCH_2 X , (CH_3)_2 CHX ltCH_3 CH_2 XltCH_2=CH CH_2 XltPh CH_2 X , Ph CH_2 Xlt(CH_3)_2 CHXltCH_3 CH_2 Xlt CH_2=CH CH_2 X , CH_2=CH-CH Xlt Ph CH_2 Xlt(CH_3)_2CHXltCH_3 CH_2 X ,