1 L of 1 `MCuSO_(4)` solution is electrolysed. After passing 2 F of electricity, molarity of `CuSO_(4)` solution will be

Options

A. `(M)/(2)`
B. `(M)/(4)`
C. M
D. 0

Answer

B

Explanation

I L of 1 `MCuSO_(4)= 1 "mol of" Cu^(2+)`
`Cu^(2+)2e^(-)rarrCu` 2 F of electricity will convert dil `Cu^(2+)` into Cu, hence `[CuSO_(4)]`=0