A current of 4 A is passed through a solution of silver nitrate to coat a metal surface of 80 `cm^(2)` with 0.005 mm thick layers of silver. If the density of silver (molar mass: 108 g `"mol"^(-1)`)is 10.8 g `cm^(-3)` , the time for which the current is passed is about

Options

A. 84.5 s
B. 90.5 s
C. 96.5 s
D. 100.5 s

Answer

C

Explanation

Volume of Ag deposited =`(80 cm^(2))(5xx10^(-4) cm)=0.04 cm^(3)`
amount of Ag deposited =`(0.432 g)/(108 mol^(-1))=0.04 mol`
Time for which 4 A current is passed =`(386C )/(4A)=96.5n` S