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Efficiency of a fuel cell is 80% and the...

Efficiency of a fuel cell is 80% and the standard heat of reaction is -300 kJ. The reaction involves two electrons in redox change. The `E^(@)`for the cell is:

A

1.24 V

B

2.48 V

C

0 V

D

0.62 V

Text Solution

Verified by Experts

The correct Answer is:
B
Efficiency =`(triangleG^(@))/(triangleH^(@))=(nE^(@)F)/(triangle H)=80`
`therefore E^(@)=80 xx(-300)xx10^(3)/(2xx96500xx100)=1.24 V`
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