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A current of 965 ampere is passed for 1 ...

A current of 965 ampere is passed for 1 sec through 1 litre solution of 0.02 N `NiSO_(4)` using Ni electrodes. What is the new concentration of `NiSO_(4)` ?

A

0.01 N

B

0.01M

C

0.002 M

D

0.02M

Text Solution

Verified by Experts

The correct Answer is:
B

`(w)/(E )=(965xx1)/(96500)=0.01` equivalent of `NiSO_(4)` present intially =`1xx0.02 =0.02` if Ni electrode are used no change in conc of `NiSO_(4)` i.e 0.02 or 0.01 M
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