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For the cell reaction, Mg(s)+2Ag^(+) (aq...

For the cell reaction, `Mg(s)+2Ag^(+) (aq.) rarr Mg^(2+) (aq) + 2Ag(s) E_(cell)^(@)` : +3.17 V at 298 K. The value of `E_(cell)^(@) triangle G^(@)` and at `Ag^(+)` and `Mg^(2+)` concentrations of 0.001 M and 0.02 M respectively are:

A

`3.04 V - 605.8 kj mol^(-1) 20000`

B

`3.04 V - 611.8 kj mol^(-1) 20000`

C

`3.13 V - 605.8 kj mol^(-1) 20000`

D

`3.04 V - 611.8 kj mol^(-1) 20000`

Text Solution

Verified by Experts

The correct Answer is:
B
`E^(@)=+3.17 Vn=2`
`E=E^(@)-(0.59)/(n)log _(10) Q=3.17 log (200000)=+3.04 V`
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