The conductivity of a saturated AgCl solution is found to be `1.86 xx 10^(-6) S cm^(-1)` and that for water is `6.0 xx 10^(-8) S cm^(-1)` . The solubility of AgCl is (molar conductivity =137.2 )

Options

A. `1.7 xx 10^(-3) mol L^(-1)`
B. `1.3 xx 10^(-5) mol L^(-1)`
C. `1.3 xx 10^(-4) mol L^(-1)`
D. `1.3 X 10^(-4)` mol `L^(-1)`

Answer

C

Explanation

`K_(AgCI)=k_(solution)-k_(water)=1.86 xx120^(-6)=k_(AgCI)xx(1000)/(wedge_(eq)^(@))=180xx10^(-8)xx(1000)/(137.2)=1.3xx10E^(-5) mol l^(-1)`