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Conductivity of 0.01 M KCI solution is x...

Conductivity of 0.01 M KCI solution is x S `cm^(-1)` . When conductivity cell is filled with 0.01 M KCl the conductance observed is y S. When the same cell is filled with 0.01M `H_(2)SO_(4)` the observed conductance is z S `cm^(-1)` . Hence conductivity of 0.01 M `H_(2)SO_(4)` is

A

xz

B

z/xy

C

xz/y

D

xy/z

Text Solution

Verified by Experts

The correct Answer is:
B
`"Cell constant" =("conducitivity of KCI")/("conductance of KCI")=(xS)/(yS)`
For 0.01 M `H_(2)SO_(4)` specific conductance = cell constant xx conductance = xz/y
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